12140351514223 has 2 divisors, whose sum is σ = 12140351514224. Its totient is φ = 12140351514222.

The previous prime is 12140351514191. The next prime is 12140351514229. The reversal of 12140351514223 is 32241515304121.

It is a strong prime.

It is an emirp because it is prime and its reverse (32241515304121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12140351514223 - 2⁵ = 12140351514191 is a prime.

It is a super-3 number, since 3×12140351514223³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12140351514229) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6070175757111 + 6070175757112.

It is an arithmetic number, because the mean of its divisors is an integer number (6070175757112).

Almost surely, 2^{12140351514223} is an apocalyptic number.

12140351514223 is a deficient number, since it is larger than the sum of its proper divisors (1).

12140351514223 is an equidigital number, since it uses as much as digits as its factorization.

12140351514223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 12140351514223 its reverse (32241515304121), we get a palindrome (44381866818344).

The spelling of 12140351514223 in words is "twelve trillion, one hundred forty billion, three hundred fifty-one million, five hundred fourteen thousand, two hundred twenty-three".