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12134351401 = 89631353827
BaseRepresentation
bin10110100110100001…
…11000001000101001
31011022122220220211021
423103100320020221
5144322343221101
65324025132441
7606462166534
oct132320701051
934278826737
1012134351401
115167585897
12242792a121
1311b4c44ab3
148317d1a1b
154b045d5a1
hex2d3438229

12134351401 has 4 divisors (see below), whose sum is σ = 12135714192. Its totient is φ = 12132988612.

The previous prime is 12134351399. The next prime is 12134351413. The reversal of 12134351401 is 10415343121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12134351401 - 21 = 12134351399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12134357401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 667951 + ... + 685876.

It is an arithmetic number, because the mean of its divisors is an integer number (3033928548).

Almost surely, 212134351401 is an apocalyptic number.

It is an amenable number.

12134351401 is a deficient number, since it is larger than the sum of its proper divisors (1362791).

12134351401 is an equidigital number, since it uses as much as digits as its factorization.

12134351401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1362790.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 12134351401 its reverse (10415343121), we get a palindrome (22549694522).

The spelling of 12134351401 in words is "twelve billion, one hundred thirty-four million, three hundred fifty-one thousand, four hundred one".

Divisors: 1 8963 1353827 12134351401