12123032030023 has 4 divisors (see below), whose sum is σ = 12123040334760. Its totient is φ = 12123023725288.

The previous prime is 12123032029993. The next prime is 12123032030063. The reversal of 12123032030023 is 32003023032121.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 12123032030023 - 2¹⁷ = 12123031898951 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12123032029976 and 12123032030003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12123032030063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1317640 + ... + 5097277.

It is an arithmetic number, because the mean of its divisors is an integer number (3030760083690).

Almost surely, 2^{12123032030023} is an apocalyptic number.

12123032030023 is a deficient number, since it is larger than the sum of its proper divisors (8304737).

12123032030023 is an equidigital number, since it uses as much as digits as its factorization.

12123032030023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8304736.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 12123032030023 its reverse (32003023032121), we get a palindrome (44126055062144).

The spelling of 12123032030023 in words is "twelve trillion, one hundred twenty-three billion, thirty-two million, thirty thousand, twenty-three".