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121121000 = 2353711313
BaseRepresentation
bin1110011100000…
…10100011101000
322102220120202222
413032002203220
5222001333000
620004013212
73000340310
oct716024350
9272816688
10121121000
1162408000
1234691208
131c12a240
141212c440
15a977a85
hex73828e8

121121000 has 256 divisors, whose sum is σ = 383685120. Its totient is φ = 34848000.

The previous prime is 121120969. The next prime is 121121003. The reversal of 121121000 is 121121.

Added to its reverse (121121) it gives a square (121242121 = 110112).

It is a Harshad number since it is a multiple of its sum of digits (8).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121121003) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9316994 + ... + 9317006.

It is an arithmetic number, because the mean of its divisors is an integer number (1498770).

Almost surely, 2121121000 is an apocalyptic number.

121121000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121121000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (191842560).

121121000 is an abundant number, since it is smaller than the sum of its proper divisors (262564120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121121000 is a wasteful number, since it uses less digits than its factorization.

121121000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74 (or 38 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 8.

The square root of 121121000 is about 11005.4986256871. The cubic root of 121121000 is about 494.7735589803.

Adding to 121121000 its reverse (121121), we get a palindrome (121242121).

121121000 divided by its reverse (121121) gives a cube (1000 = 103).

It can be divided in two parts, 121 and 121000, that added together give a palindrome (121121).

The spelling of 121121000 in words is "one hundred twenty-one million, one hundred twenty-one thousand".