Base | Representation |
---|---|
bin | 11011010101100110111001… |
… | …100001100110110001011011 |
3 | 120202201002011000022002212202 |
4 | 123111212321201212301123 |
5 | 111224340401310031301 |
6 | 1103413513505400415 |
7 | 34216325213445323 |
oct | 3325467141466133 |
9 | 522632130262782 |
10 | 120232132111451 |
11 | 3534518514a318 |
12 | 1159996193910b |
13 | 5211ac2762b39 |
14 | 21993a2804283 |
15 | dd77a89b066b |
hex | 6d59b9866c5b |
120232132111451 has 2 divisors, whose sum is σ = 120232132111452. Its totient is φ = 120232132111450.
The previous prime is 120232132111411. The next prime is 120232132111477. The reversal of 120232132111451 is 154111231232021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120232132111451 - 242 = 115834085600347 is a prime.
It is not a weakly prime, because it can be changed into another prime (120232132111411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60116066055725 + 60116066055726.
It is an arithmetic number, because the mean of its divisors is an integer number (60116066055726).
Almost surely, 2120232132111451 is an apocalyptic number.
120232132111451 is a deficient number, since it is larger than the sum of its proper divisors (1).
120232132111451 is an equidigital number, since it uses as much as digits as its factorization.
120232132111451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 120232132111451 its reverse (154111231232021), we get a palindrome (274343363343472).
The spelling of 120232132111451 in words is "one hundred twenty trillion, two hundred thirty-two billion, one hundred thirty-two million, one hundred eleven thousand, four hundred fifty-one".
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