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12022211303 is a prime number
BaseRepresentation
bin10110011001001010…
…00110001011100111
31011000211220121112022
423030211012023213
5144110141230203
65304541413355
7603631052504
oct131445061347
934024817468
1012022211303
11510a252323
1223b626a25b
1311979405cb
148209604ab
154a56aba38
hex2cc9462e7

12022211303 has 2 divisors, whose sum is σ = 12022211304. Its totient is φ = 12022211302.

The previous prime is 12022211293. The next prime is 12022211309. The reversal of 12022211303 is 30311222021.

12022211303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12022211303 - 210 = 12022210279 is a prime.

It is a super-2 number, since 2×120222113032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12022211309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011105651 + 6011105652.

It is an arithmetic number, because the mean of its divisors is an integer number (6011105652).

Almost surely, 212022211303 is an apocalyptic number.

12022211303 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022211303 is an equidigital number, since it uses as much as digits as its factorization.

12022211303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12022211303 its reverse (30311222021), we get a palindrome (42333433324).

The spelling of 12022211303 in words is "twelve billion, twenty-two million, two hundred eleven thousand, three hundred three".