Base | Representation |
---|---|
bin | 110111111110101000… |
… | …0001100111110110001 |
3 | 102111021211222010201112 |
4 | 1233331100030332301 |
5 | 3432144012000423 |
6 | 131120341443105 |
7 | 11453663432663 |
oct | 1577520147661 |
9 | 374254863645 |
10 | 120213000113 |
11 | 46a89117278 |
12 | 1b36b110495 |
13 | b44a37393b |
14 | 5b65750533 |
15 | 31d8a2ba78 |
hex | 1bfd40cfb1 |
120213000113 has 4 divisors (see below), whose sum is σ = 123145024548. Its totient is φ = 117280975680.
The previous prime is 120213000101. The next prime is 120213000169. The reversal of 120213000113 is 311000312021.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 65696353969 + 54516646144 = 256313^2 + 233488^2 .
It is a cyclic number.
It is not a de Polignac number, because 120213000113 - 212 = 120212996017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120213000613) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1466012156 + ... + 1466012237.
It is an arithmetic number, because the mean of its divisors is an integer number (30786256137).
Almost surely, 2120213000113 is an apocalyptic number.
It is an amenable number.
120213000113 is a deficient number, since it is larger than the sum of its proper divisors (2932024435).
120213000113 is an equidigital number, since it uses as much as digits as its factorization.
120213000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2932024434.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 120213000113 its reverse (311000312021), we get a palindrome (431213312134).
The spelling of 120213000113 in words is "one hundred twenty billion, two hundred thirteen million, one hundred thirteen", and thus it is an aban number.
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