120193 has 2 divisors, whose sum is σ = 120194. Its totient is φ = 120192.

The previous prime is 120181. The next prime is 120199. The reversal of 120193 is 391021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 82944 + 37249 = 288^2 + 193^2 .

It is an emirp because it is prime and its reverse (391021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120193 is a prime.

It is not a weakly prime, because it can be changed into another prime (120199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60096 + 60097.

It is an arithmetic number, because the mean of its divisors is an integer number (60097).

2¹²⁰¹⁹³ is an apocalyptic number.

It is an amenable number.

120193 is a deficient number, since it is larger than the sum of its proper divisors (1).

120193 is an equidigital number, since it uses as much as digits as its factorization.

120193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

The square root of 120193 is about 346.6886210997. The cubic root of 120193 is about 49.3506705966.

It can be divided in two parts, 120 and 193, that added together give a palindrome (313).

The spelling of 120193 in words is "one hundred twenty thousand, one hundred ninety-three".