1201430051 has 2 divisors, whose sum is σ = 1201430052. Its totient is φ = 1201430050.

The previous prime is 1201430003. The next prime is 1201430053. The reversal of 1201430051 is 1500341021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1201430051 - 2¹⁴ = 1201413667 is a prime.

It is a super-3 number, since 3×1201430051³ (a number of 28 digits) contains 333 as substring.

Together with 1201430053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1201430053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600715025 + 600715026.

It is an arithmetic number, because the mean of its divisors is an integer number (600715026).

Almost surely, 2^1201430051 is an apocalyptic number.

1201430051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201430051 is an equidigital number, since it uses as much as digits as its factorization.

1201430051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 1201430051 is about 34661.6510137645. The cubic root of 1201430051 is about 1063.0805282621.

Adding to 1201430051 its reverse (1500341021), we get a palindrome (2701771072).

The spelling of 1201430051 in words is "one billion, two hundred one million, four hundred thirty thousand, fifty-one".