120133410131441 has 4 divisors (see below), whose sum is σ = 137295325864512. Its totient is φ = 102971494398372.

The previous prime is 120133410131419. The next prime is 120133410131473. The reversal of 120133410131441 is 144131014331021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120133410131441 - 2⁴⁶ = 49764665953777 is a prime.

It is a super-2 number, since 2×120133410131441² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120133410131491) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8580957866525 + ... + 8580957866538.

It is an arithmetic number, because the mean of its divisors is an integer number (34323831466128).

Almost surely, 2^{120133410131441} is an apocalyptic number.

It is an amenable number.

120133410131441 is a deficient number, since it is larger than the sum of its proper divisors (17161915733071).

120133410131441 is an equidigital number, since it uses as much as digits as its factorization.

120133410131441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17161915733070.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 120133410131441 its reverse (144131014331021), we get a palindrome (264264424462462).

The spelling of 120133410131441 in words is "one hundred twenty trillion, one hundred thirty-three billion, four hundred ten million, one hundred thirty-one thousand, four hundred forty-one".