Base | Representation |
---|---|
bin | 11011010100001001101010… |
… | …011000010100101001001110 |
3 | 120202100111202000202102211022 |
4 | 123110021222120110221032 |
5 | 111221220334111430110 |
6 | 1103255515500154142 |
7 | 34206152306005661 |
oct | 3324115230245116 |
9 | 522314660672738 |
10 | 120132020030030 |
11 | 35306781520848 |
12 | 11582482538952 |
13 | 520552996c838 |
14 | 21945c69296d8 |
15 | dd4d999d6755 |
hex | 6d426a614a4e |
120132020030030 has 8 divisors (see below), whose sum is σ = 216237636054072. Its totient is φ = 48052808012008.
The previous prime is 120132020029937. The next prime is 120132020030119. The reversal of 120132020030030 is 30030020231021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 120132020029990 and 120132020030008.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6006601001492 + ... + 6006601001511.
It is an arithmetic number, because the mean of its divisors is an integer number (27029704506759).
Almost surely, 2120132020030030 is an apocalyptic number.
120132020030030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
120132020030030 is a deficient number, since it is larger than the sum of its proper divisors (96105616024042).
120132020030030 is a wasteful number, since it uses less digits than its factorization.
120132020030030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12013202003010.
The product of its (nonzero) digits is 216, while the sum is 17.
Adding to 120132020030030 its reverse (30030020231021), we get a palindrome (150162040261051).
The spelling of 120132020030030 in words is "one hundred twenty trillion, one hundred thirty-two billion, twenty million, thirty thousand, thirty".
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