Base | Representation |
---|---|
bin | 11011010100001001101010… |
… | …011000010000000101000011 |
3 | 120202100111202000201111011202 |
4 | 123110021222120100011003 |
5 | 111221220334110330311 |
6 | 1103255515455531415 |
7 | 34206152305600316 |
oct | 3324115230200503 |
9 | 522314660644152 |
10 | 120132020011331 |
11 | 35306781508799 |
12 | 11582482529b6b |
13 | 5205529964183 |
14 | 21945c692297d |
15 | dd4d999d0e3b |
hex | 6d426a610143 |
120132020011331 has 16 divisors (see below), whose sum is σ = 123565121226240. Its totient is φ = 116736624969120.
The previous prime is 120132020011291. The next prime is 120132020011397. The reversal of 120132020011331 is 133110020231021.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120132020011331 is a prime.
It is a super-3 number, since 3×1201320200113313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (120132020011931) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3221000 + ... + 15831578.
It is an arithmetic number, because the mean of its divisors is an integer number (7722820076640).
Almost surely, 2120132020011331 is an apocalyptic number.
120132020011331 is a deficient number, since it is larger than the sum of its proper divisors (3433101214909).
120132020011331 is a wasteful number, since it uses less digits than its factorization.
120132020011331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12612074.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 120132020011331 its reverse (133110020231021), we get a palindrome (253242040242352).
The spelling of 120132020011331 in words is "one hundred twenty trillion, one hundred thirty-two billion, twenty million, eleven thousand, three hundred thirty-one".
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