Base | Representation |
---|---|
bin | 10110011000000100… |
… | …10101110100101011 |
3 | 1011000012202201121220 |
4 | 23030002111310223 |
5 | 144100323202311 |
6 | 5304014233123 |
7 | 603460445061 |
oct | 131402256453 |
9 | 34005681556 |
10 | 12013100331 |
11 | 510509a0a1 |
12 | 23b31b57a3 |
13 | 1195aa05bb |
14 | 81d66c031 |
15 | 4a49ac206 |
hex | 2cc095d2b |
12013100331 has 16 divisors (see below), whose sum is σ = 16841436960. Its totient is φ = 7605803520.
The previous prime is 12013100329. The next prime is 12013100347. The reversal of 12013100331 is 13300131021.
It is not a de Polignac number, because 12013100331 - 21 = 12013100329 is a prime.
It is a super-2 number, since 2×120131003312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12013100331.
It is not an unprimeable number, because it can be changed into a prime (12013100311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1126510 + ... + 1137123.
It is an arithmetic number, because the mean of its divisors is an integer number (1052589810).
Almost surely, 212013100331 is an apocalyptic number.
12013100331 is a deficient number, since it is larger than the sum of its proper divisors (4828336629).
12013100331 is a wasteful number, since it uses less digits than its factorization.
12013100331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2263726.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 12013100331 its reverse (13300131021), we get a palindrome (25313231352).
The spelling of 12013100331 in words is "twelve billion, thirteen million, one hundred thousand, three hundred thirty-one".
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