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12013100331 = 329612263633
BaseRepresentation
bin10110011000000100…
…10101110100101011
31011000012202201121220
423030002111310223
5144100323202311
65304014233123
7603460445061
oct131402256453
934005681556
1012013100331
11510509a0a1
1223b31b57a3
131195aa05bb
1481d66c031
154a49ac206
hex2cc095d2b

12013100331 has 16 divisors (see below), whose sum is σ = 16841436960. Its totient is φ = 7605803520.

The previous prime is 12013100329. The next prime is 12013100347. The reversal of 12013100331 is 13300131021.

It is not a de Polignac number, because 12013100331 - 21 = 12013100329 is a prime.

It is a super-2 number, since 2×120131003312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12013100331.

It is not an unprimeable number, because it can be changed into a prime (12013100311) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1126510 + ... + 1137123.

It is an arithmetic number, because the mean of its divisors is an integer number (1052589810).

Almost surely, 212013100331 is an apocalyptic number.

12013100331 is a deficient number, since it is larger than the sum of its proper divisors (4828336629).

12013100331 is a wasteful number, since it uses less digits than its factorization.

12013100331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2263726.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 12013100331 its reverse (13300131021), we get a palindrome (25313231352).

The spelling of 12013100331 in words is "twelve billion, thirteen million, one hundred thousand, three hundred thirty-one".

Divisors: 1 3 29 61 87 183 1769 5307 2263633 6790899 65645357 138081613 196936071 414244839 4004366777 12013100331