12012110000041 has 2 divisors, whose sum is σ = 12012110000042. Its totient is φ = 12012110000040.

The previous prime is 12012109999997. The next prime is 12012110000153. The reversal of 12012110000041 is 14000001121021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11940618470400 + 71491529641 = 3455520^2 + 267379^2 .

It is an emirp because it is prime and its reverse (14000001121021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12012110000041 - 2¹⁹ = 12012109475753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12012109999976 and 12012110000030.

It is not a weakly prime, because it can be changed into another prime (12012110040041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6006055000020 + 6006055000021.

It is an arithmetic number, because the mean of its divisors is an integer number (6006055000021).

Almost surely, 2^{12012110000041} is an apocalyptic number.

It is an amenable number.

12012110000041 is a deficient number, since it is larger than the sum of its proper divisors (1).

12012110000041 is an equidigital number, since it uses as much as digits as its factorization.

12012110000041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 12012110000041 its reverse (14000001121021), we get a palindrome (26012111121062).

The spelling of 12012110000041 in words is "twelve trillion, twelve billion, one hundred ten million, forty-one", and thus it is an aban number.