12003103130033 has 4 divisors (see below), whose sum is σ = 12009397365360. Its totient is φ = 11996808894708.

The previous prime is 12003103130027. The next prime is 12003103130077. The reversal of 12003103130033 is 33003130130021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12003103130033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12003103129987 and 12003103130014.

It is not an unprimeable number, because it can be changed into a prime (12003103130533) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3147114803 + ... + 3147118616.

It is an arithmetic number, because the mean of its divisors is an integer number (3002349341340).

Almost surely, 2^{12003103130033} is an apocalyptic number.

It is an amenable number.

12003103130033 is a deficient number, since it is larger than the sum of its proper divisors (6294235327).

12003103130033 is an equidigital number, since it uses as much as digits as its factorization.

12003103130033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6294235326.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 12003103130033 its reverse (33003130130021), we get a palindrome (45006233260054).

The spelling of 12003103130033 in words is "twelve trillion, three billion, one hundred three million, one hundred thirty thousand, thirty-three".