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12002132122003 = 46325922531581
BaseRepresentation
bin1010111010100111011011…
…0100100101100110010011
31120111101121020001010100001
42232221312310211212103
53033120331310401003
641305411532510431
72346061010523442
oct256516664454623
946441536033301
1012002132122003
113908091762701
12141a11591b417
13690a4734653a
142d6c98c2ad59
1515c30a1d061d
hexaea76d25993

12002132122003 has 4 divisors (see below), whose sum is σ = 12028054654048. Its totient is φ = 11976209589960.

The previous prime is 12002132121997. The next prime is 12002132122067. The reversal of 12002132122003 is 30022123120021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12002132122003 - 221 = 12002130024851 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12002132122103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12961265328 + ... + 12961266253.

It is an arithmetic number, because the mean of its divisors is an integer number (3007013663512).

Almost surely, 212002132122003 is an apocalyptic number.

12002132122003 is a deficient number, since it is larger than the sum of its proper divisors (25922532045).

12002132122003 is an equidigital number, since it uses as much as digits as its factorization.

12002132122003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25922532044.

The product of its (nonzero) digits is 288, while the sum is 19.

Adding to 12002132122003 its reverse (30022123120021), we get a palindrome (42024255242024).

The spelling of 12002132122003 in words is "twelve trillion, two billion, one hundred thirty-two million, one hundred twenty-two thousand, three".

Divisors: 1 463 25922531581 12002132122003