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12002023130002 = 26001011565001
BaseRepresentation
bin1010111010100111000001…
…0100110100001110010010
31120111101022121221202102021
42232221300110310032102
53033120120410130002
641305353040442054
72346055215230503
oct256516024641622
946441277852367
1012002023130002
11390803618a374
12141a0a531932a
13690a2a8a4c29
142d6c88578baa
1515c300851737
hexaea70534392

12002023130002 has 4 divisors (see below), whose sum is σ = 18003034695006. Its totient is φ = 6001011565000.

The previous prime is 12002023129897. The next prime is 12002023130003. The reversal of 12002023130002 is 20003132020021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11497327974441 + 504695155561 = 3390771^2 + 710419^2 .

It is a super-3 number, since 3×120020231300023 (a number of 40 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (12002023130003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3000505782499 + ... + 3000505782502.

Almost surely, 212002023130002 is an apocalyptic number.

12002023130002 is a deficient number, since it is larger than the sum of its proper divisors (6001011565004).

12002023130002 is an equidigital number, since it uses as much as digits as its factorization.

12002023130002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6001011565003.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 12002023130002 its reverse (20003132020021), we get a palindrome (32005155150023).

The spelling of 12002023130002 in words is "twelve trillion, two billion, twenty-three million, one hundred thirty thousand, two".

Divisors: 1 2 6001011565001 12002023130002