120001002113 has 2 divisors, whose sum is σ = 120001002114. Its totient is φ = 120001002112.

The previous prime is 120001002091. The next prime is 120001002127. The reversal of 120001002113 is 311200100021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70613495824 + 49387506289 = 265732^2 + 222233^2 .

It is an emirp because it is prime and its reverse (311200100021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120001002113 - 2¹⁶ = 120000936577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120001002094 and 120001002103.

It is not a weakly prime, because it can be changed into another prime (120901002113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60000501056 + 60000501057.

It is an arithmetic number, because the mean of its divisors is an integer number (60000501057).

Almost surely, 2^120001002113 is an apocalyptic number.

It is an amenable number.

120001002113 is a deficient number, since it is larger than the sum of its proper divisors (1).

120001002113 is an equidigital number, since it uses as much as digits as its factorization.

120001002113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 120001002113 its reverse (311200100021), we get a palindrome (431201102134).

The spelling of 120001002113 in words is "one hundred twenty billion, one million, two thousand, one hundred thirteen".