Base | Representation |
---|---|
bin | 10110010101000101… |
… | …00000101011111011 |
3 | 1010221110111102122100 |
4 | 23022202200223323 |
5 | 144022410312003 |
6 | 5301315554443 |
7 | 603034066050 |
oct | 131242405373 |
9 | 33843442570 |
10 | 11987979003 |
11 | 50a19a1070 |
12 | 23a68bba23 |
13 | 1190816100 |
14 | 81a1ad027 |
15 | 4a2698ba3 |
hex | 2ca8a0afb |
11987979003 has 72 divisors (see below), whose sum is σ = 23377386240. Its totient is φ = 5748425280.
The previous prime is 11987978993. The next prime is 11987979011. The reversal of 11987979003 is 30097978911.
11987979003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11987979003 - 28 = 11987978747 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11987979013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 65938 + ... + 168296.
It is an arithmetic number, because the mean of its divisors is an integer number (324685920).
Almost surely, 211987979003 is an apocalyptic number.
11987979003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11987979003 is a deficient number, since it is larger than the sum of its proper divisors (11389407237).
11987979003 is a wasteful number, since it uses less digits than its factorization.
11987979003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 102409 (or 102393 counting only the distinct ones).
The product of its (nonzero) digits is 857304, while the sum is 54.
The spelling of 11987979003 in words is "eleven billion, nine hundred eighty-seven million, nine hundred seventy-nine thousand, three".
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