Base | Representation |
---|---|
bin | 10110000110010110… |
… | …10010101111110001 |
3 | 1010121212001121120011 |
4 | 23003023102233301 |
5 | 143244244431311 |
6 | 5241144214521 |
7 | 600004115206 |
oct | 130313225761 |
9 | 33555047504 |
10 | 11864452081 |
11 | 50391a04a9 |
12 | 237146a441 |
13 | 1171055a61 |
14 | 807a15cad |
15 | 4968e8321 |
hex | 2c32d2bf1 |
11864452081 has 2 divisors, whose sum is σ = 11864452082. Its totient is φ = 11864452080.
The previous prime is 11864452057. The next prime is 11864452087. The reversal of 11864452081 is 18025446811.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8490701025 + 3373751056 = 92145^2 + 58084^2 .
It is a cyclic number.
It is not a de Polignac number, because 11864452081 - 25 = 11864452049 is a prime.
It is a super-2 number, since 2×118644520812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11864452087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5932226040 + 5932226041.
It is an arithmetic number, because the mean of its divisors is an integer number (5932226041).
Almost surely, 211864452081 is an apocalyptic number.
It is an amenable number.
11864452081 is a deficient number, since it is larger than the sum of its proper divisors (1).
11864452081 is an equidigital number, since it uses as much as digits as its factorization.
11864452081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61440, while the sum is 40.
Adding to 11864452081 its reverse (18025446811), we get a palindrome (29889898892).
The spelling of 11864452081 in words is "eleven billion, eight hundred sixty-four million, four hundred fifty-two thousand, eighty-one".
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