1154331013 has 4 divisors (see below), whose sum is σ = 1259270208. Its totient is φ = 1049391820.

The previous prime is 1154331011. The next prime is 1154331023. The reversal of 1154331013 is 3101334511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1154331013 - 2¹ = 1154331011 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1154331011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52469581 + ... + 52469602.

It is an arithmetic number, because the mean of its divisors is an integer number (314817552).

Almost surely, 2^1154331013 is an apocalyptic number.

It is an amenable number.

1154331013 is a deficient number, since it is larger than the sum of its proper divisors (104939195).

1154331013 is a wasteful number, since it uses less digits than its factorization.

1154331013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104939194.

The product of its (nonzero) digits is 540, while the sum is 22.

The square root of 1154331013 is about 33975.4472082414. The cubic root of 1154331013 is about 1049.0031394522.

Adding to 1154331013 its reverse (3101334511), we get a palindrome (4255665524).

The spelling of 1154331013 in words is "one billion, one hundred fifty-four million, three hundred thirty-one thousand, thirteen".