115231244055451 has 4 divisors (see below), whose sum is σ = 115231278290112. Its totient is φ = 115231209820792.

The previous prime is 115231244055439. The next prime is 115231244055457. The reversal of 115231244055451 is 154550442132511.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 115231244055451 - 2¹¹ = 115231244053403 is a prime.

It is a super-2 number, since 2×115231244055451² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 115231244055398 and 115231244055407.

It is not an unprimeable number, because it can be changed into a prime (115231244055457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11440996 + ... + 19009441.

It is an arithmetic number, because the mean of its divisors is an integer number (28807819572528).

Almost surely, 2^{115231244055451} is an apocalyptic number.

115231244055451 is a deficient number, since it is larger than the sum of its proper divisors (34234661).

115231244055451 is an equidigital number, since it uses as much as digits as its factorization.

115231244055451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34234660.

The product of its (nonzero) digits is 480000, while the sum is 43.

Adding to 115231244055451 its reverse (154550442132511), we get a palindrome (269781686187962).

The spelling of 115231244055451 in words is "one hundred fifteen trillion, two hundred thirty-one billion, two hundred forty-four million, fifty-five thousand, four hundred fifty-one".