Base | Representation |
---|---|
bin | 1101101110001… |
… | …01100100101111 |
3 | 22000120220001212 |
4 | 12313011210233 |
5 | 213431312142 |
6 | 15231025035 |
7 | 2565240212 |
oct | 667054457 |
9 | 260526055 |
10 | 115104047 |
11 | 59a78413 |
12 | 3266b17b |
13 | 1ab01606 |
14 | 11403779 |
15 | a189d82 |
hex | 6dc592f |
115104047 has 2 divisors, whose sum is σ = 115104048. Its totient is φ = 115104046.
The previous prime is 115104007. The next prime is 115104053. The reversal of 115104047 is 740401511.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (740401511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 115104047 - 212 = 115099951 is a prime.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115104007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57552023 + 57552024.
It is an arithmetic number, because the mean of its divisors is an integer number (57552024).
Almost surely, 2115104047 is an apocalyptic number.
115104047 is a deficient number, since it is larger than the sum of its proper divisors (1).
115104047 is an equidigital number, since it uses as much as digits as its factorization.
115104047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 560, while the sum is 23.
The square root of 115104047 is about 10728.6554143565. The cubic root of 115104047 is about 486.4410282486.
Adding to 115104047 its reverse (740401511), we get a palindrome (855505558).
The spelling of 115104047 in words is "one hundred fifteen million, one hundred four thousand, forty-seven".
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