Base | Representation |
---|---|
bin | 1010011101111110100110… |
… | …0000100110000110110010 |
3 | 1111202100200002200212001012 |
4 | 2213133221200212012302 |
5 | 3002040224031201002 |
6 | 40251403311310522 |
7 | 2265402606263051 |
oct | 247375140460662 |
9 | 44670602625035 |
10 | 11510135022002 |
11 | 373846a173451 |
12 | 135a8a8b1b442 |
13 | 65652a215866 |
14 | 2bb144828398 |
15 | 14e611e6bd52 |
hex | a77e98261b2 |
11510135022002 has 4 divisors (see below), whose sum is σ = 17265202533006. Its totient is φ = 5755067511000.
The previous prime is 11510135021971. The next prime is 11510135022083. The reversal of 11510135022002 is 20022053101511.
11510135022002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11452058359921 + 58076662081 = 3384089^2 + 240991^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2877533755499 + ... + 2877533755502.
Almost surely, 211510135022002 is an apocalyptic number.
11510135022002 is a deficient number, since it is larger than the sum of its proper divisors (5755067511004).
11510135022002 is an equidigital number, since it uses as much as digits as its factorization.
11510135022002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5755067511003.
The product of its (nonzero) digits is 600, while the sum is 23.
Adding to 11510135022002 its reverse (20022053101511), we get a palindrome (31532188123513).
The spelling of 11510135022002 in words is "eleven trillion, five hundred ten billion, one hundred thirty-five million, twenty-two thousand, two".
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