1141524051113 has 2 divisors, whose sum is σ = 1141524051114. Its totient is φ = 1141524051112.

The previous prime is 1141524051103. The next prime is 1141524051131. The reversal of 1141524051113 is 3111504251411.

Together with next prime (1141524051131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1065090049024 + 76434002089 = 1032032^2 + 276467^2 .

It is a cyclic number.

It is not a de Polignac number, because 1141524051113 - 2¹⁶ = 1141523985577 is a prime.

It is a super-4 number, since 4×1141524051113⁴ (a number of 49 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (1141524051103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570762025556 + 570762025557.

It is an arithmetic number, because the mean of its divisors is an integer number (570762025557).

Almost surely, 2^{1141524051113} is an apocalyptic number.

It is an amenable number.

1141524051113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141524051113 is an equidigital number, since it uses as much as digits as its factorization.

1141524051113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2400, while the sum is 29.

The spelling of 1141524051113 in words is "one trillion, one hundred forty-one billion, five hundred twenty-four million, fifty-one thousand, one hundred thirteen".