Base | Representation |
---|---|
bin | 11001111100011100000010… |
… | …100111010001011110011111 |
3 | 112222000021111121112022122121 |
4 | 121330130002213101132133 |
5 | 104423441343120034323 |
6 | 1042402504525323411 |
7 | 33014526252065041 |
oct | 3174340247213637 |
9 | 488007447468577 |
10 | 114104440002463 |
11 | 333a246a759489 |
12 | 1096a256106567 |
13 | 4b89005707301 |
14 | 2026981c6da91 |
15 | d2d1b95e3a5d |
hex | 67c7029d179f |
114104440002463 has 2 divisors, whose sum is σ = 114104440002464. Its totient is φ = 114104440002462.
The previous prime is 114104440002349. The next prime is 114104440002467. The reversal of 114104440002463 is 364200044401411.
It is a strong prime.
It is an emirp because it is prime and its reverse (364200044401411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114104440002463 - 213 = 114104439994271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (114104440002467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57052220001231 + 57052220001232.
It is an arithmetic number, because the mean of its divisors is an integer number (57052220001232).
Almost surely, 2114104440002463 is an apocalyptic number.
114104440002463 is a deficient number, since it is larger than the sum of its proper divisors (1).
114104440002463 is an equidigital number, since it uses as much as digits as its factorization.
114104440002463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 34.
Adding to 114104440002463 its reverse (364200044401411), we get a palindrome (478304484403874).
The spelling of 114104440002463 in words is "one hundred fourteen trillion, one hundred four billion, four hundred forty million, two thousand, four hundred sixty-three".
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