Base | Representation |
---|---|
bin | 1010011000001011001101… |
… | …1101100001101111100111 |
3 | 1111101211100110110020020121 |
4 | 2212002303131201233213 |
5 | 2443422042131001411 |
6 | 40133515142542411 |
7 | 2255243303466523 |
oct | 246026335415747 |
9 | 44354313406217 |
10 | 11410444000231 |
11 | 36aa162194261 |
12 | 1343506737a07 |
13 | 64a000728693 |
14 | 2b63a8836d83 |
15 | 14bc29e16571 |
hex | a60b3761be7 |
11410444000231 has 2 divisors, whose sum is σ = 11410444000232. Its totient is φ = 11410444000230.
The previous prime is 11410444000223. The next prime is 11410444000297. The reversal of 11410444000231 is 13200044401411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11410444000231 - 23 = 11410444000223 is a prime.
It is a super-2 number, since 2×114104440002312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11410444000196 and 11410444000205.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11410444000331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705222000115 + 5705222000116.
It is an arithmetic number, because the mean of its divisors is an integer number (5705222000116).
Almost surely, 211410444000231 is an apocalyptic number.
11410444000231 is a deficient number, since it is larger than the sum of its proper divisors (1).
11410444000231 is an equidigital number, since it uses as much as digits as its factorization.
11410444000231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 11410444000231 its reverse (13200044401411), we get a palindrome (24610488401642).
The spelling of 11410444000231 in words is "eleven trillion, four hundred ten billion, four hundred forty-four million, two hundred thirty-one", and thus it is an aban number.
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