Base | Representation |
---|---|
bin | 10101001111101001… |
… | …00101000110101011 |
3 | 1002102212111002200021 |
4 | 22213310211012223 |
5 | 141324302410011 |
6 | 5123431421311 |
7 | 552432155605 |
oct | 124764450653 |
9 | 32385432607 |
10 | 11405513131 |
11 | 4923129911 |
12 | 2263824837 |
13 | 10c9c4944c |
14 | 7a2aac175 |
15 | 46b491471 |
hex | 2a7d251ab |
11405513131 has 4 divisors (see below), whose sum is σ = 11416707000. Its totient is φ = 11394319264.
The previous prime is 11405513123. The next prime is 11405513191. The reversal of 11405513131 is 13131550411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11405513131 - 23 = 11405513123 is a prime.
It is a super-2 number, since 2×114055131312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11405513096 and 11405513105.
It is not an unprimeable number, because it can be changed into a prime (11405513101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5595406 + ... + 5597443.
It is an arithmetic number, because the mean of its divisors is an integer number (2854176750).
Almost surely, 211405513131 is an apocalyptic number.
11405513131 is a deficient number, since it is larger than the sum of its proper divisors (11193869).
11405513131 is a wasteful number, since it uses less digits than its factorization.
11405513131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11193868.
The product of its (nonzero) digits is 900, while the sum is 25.
The spelling of 11405513131 in words is "eleven billion, four hundred five million, five hundred thirteen thousand, one hundred thirty-one".
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