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114012533141113 = 732239697550479
BaseRepresentation
bin11001111011000110011100…
…100010011010111001111001
3112221200111021110120000111211
4121323012130202122321321
5104420440131441003423
61042252345030323121
733005063566463665
oct3173063442327171
9487614243500454
10114012533141113
1133367497726222
12109544867b94a1
134b8044981b409
1420223439dd8a5
15d2aadab5110d
hex67b19c89ae79

114012533141113 has 8 divisors (see below), whose sum is σ = 115625967564800. Its totient is φ = 112400493823008.

The previous prime is 114012533141071. The next prime is 114012533141123. The reversal of 114012533141113 is 311141335210411.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 114012533141113 - 229 = 114011996270201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (114012533141123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 348611793 + ... + 348938686.

It is an arithmetic number, because the mean of its divisors is an integer number (14453245945600).

Almost surely, 2114012533141113 is an apocalyptic number.

It is an amenable number.

114012533141113 is a deficient number, since it is larger than the sum of its proper divisors (1613434423687).

114012533141113 is an equidigital number, since it uses as much as digits as its factorization.

114012533141113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 697552791.

The product of its (nonzero) digits is 4320, while the sum is 31.

Adding to 114012533141113 its reverse (311141335210411), we get a palindrome (425153868351524).

The spelling of 114012533141113 in words is "one hundred fourteen trillion, twelve billion, five hundred thirty-three million, one hundred forty-one thousand, one hundred thirteen".

Divisors: 1 73 2239 163447 697550479 50921184967 1561815522481 114012533141113