11324403433 has 8 divisors (see below), whose sum is σ = 13019674752. Its totient is φ = 9648506976.

The previous prime is 11324403383. The next prime is 11324403451. The reversal of 11324403433 is 33430442311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11324403433 is a prime.

It is a super-2 number, since 2×11324403433² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (11324403473) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4842460 + ... + 4844797.

It is an arithmetic number, because the mean of its divisors is an integer number (1627459344).

Almost surely, 2^11324403433 is an apocalyptic number.

It is an amenable number.

11324403433 is a deficient number, since it is larger than the sum of its proper divisors (1695271319).

11324403433 is an equidigital number, since it uses as much as digits as its factorization.

11324403433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9687431.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 11324403433 its reverse (33430442311), we get a palindrome (44754845744).

The spelling of 11324403433 in words is "eleven billion, three hundred twenty-four million, four hundred three thousand, four hundred thirty-three".