11314013014441 has 4 divisors (see below), whose sum is σ = 11334926162884. Its totient is φ = 11293099866000.

The previous prime is 11314013014393. The next prime is 11314013014463. The reversal of 11314013014441 is 14441031041311.

11314013014441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5360632612416 + 5953380402025 = 2315304^2 + 2439955^2 .

It is a cyclic number.

It is not a de Polignac number, because 11314013014441 - 2²⁵ = 11313979460009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11314013014481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10456573410 + ... + 10456574491.

It is an arithmetic number, because the mean of its divisors is an integer number (2833731540721).

Almost surely, 2^{11314013014441} is an apocalyptic number.

It is an amenable number.

11314013014441 is a deficient number, since it is larger than the sum of its proper divisors (20913148443).

11314013014441 is an equidigital number, since it uses as much as digits as its factorization.

11314013014441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20913148442.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 11314013014441 its reverse (14441031041311), we get a palindrome (25755044055752).

The spelling of 11314013014441 in words is "eleven trillion, three hundred fourteen billion, thirteen million, fourteen thousand, four hundred forty-one".