1131401023 has 2 divisors, whose sum is σ = 1131401024. Its totient is φ = 1131401022.

The previous prime is 1131400997. The next prime is 1131401039. The reversal of 1131401023 is 3201041311.

It is an a-pointer prime, because the next prime (1131401039) can be obtained adding 1131401023 to its sum of digits (16).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1131401023 - 2⁹ = 1131400511 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1131400988 and 1131401006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131401053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565700511 + 565700512.

It is an arithmetic number, because the mean of its divisors is an integer number (565700512).

Almost surely, 2^1131401023 is an apocalyptic number.

1131401023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131401023 is an equidigital number, since it uses as much as digits as its factorization.

1131401023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1131401023 is about 33636.3051329958. The cubic root of 1131401023 is about 1042.0107250564.

Adding to 1131401023 its reverse (3201041311), we get a palindrome (4332442334).

The spelling of 1131401023 in words is "one billion, one hundred thirty-one million, four hundred one thousand, twenty-three".