Base | Representation |
---|---|
bin | 1010010010100001011001… |
… | …1111111001111101110110 |
3 | 1111001112122210222220010020 |
4 | 2210220112133321331312 |
5 | 2440324140224222220 |
6 | 40021133522510010 |
7 | 2245234435361352 |
oct | 244502637717566 |
9 | 44045583886106 |
10 | 11313321320310 |
11 | 3671a52a47339 |
12 | 1328720505306 |
13 | 640ac30787c9 |
14 | 2b17d39a6462 |
15 | 1494435db040 |
hex | a4a167f9f76 |
11313321320310 has 64 divisors (see below), whose sum is σ = 28753406910144. Its totient is φ = 2839000985600.
The previous prime is 11313321320281. The next prime is 11313321320311. The reversal of 11313321320310 is 1302312331311.
It is a super-2 number, since 2×113133213203102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11313321320311) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1807600 + ... + 5088620.
It is an arithmetic number, because the mean of its divisors is an integer number (449271982971).
Almost surely, 211313321320310 is an apocalyptic number.
11313321320310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11313321320310 is an abundant number, since it is smaller than the sum of its proper divisors (17440085589834).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11313321320310 is a wasteful number, since it uses less digits than its factorization.
11313321320310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3287809.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 11313321320310 its reverse (1302312331311), we get a palindrome (12615633651621).
The spelling of 11313321320310 in words is "eleven trillion, three hundred thirteen billion, three hundred twenty-one million, three hundred twenty thousand, three hundred ten".
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