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11312143 = 23774759
BaseRepresentation
bin101011001001…
…110000001111
3210021201100021
4223021300033
510343442033
61042243011
7165103003
oct53116017
923251307
1011312143
116426a87
123956467
132460b9b
141706703
15ed6b2d
hexac9c0f

11312143 has 4 divisors (see below), whose sum is σ = 11319280. Its totient is φ = 11305008.

The previous prime is 11312111. The next prime is 11312177. The reversal of 11312143 is 34121311.

11312143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 34121311 = 74874473.

It is a cyclic number.

It is not a de Polignac number, because 11312143 - 25 = 11312111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11312183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3 + ... + 4756.

It is an arithmetic number, because the mean of its divisors is an integer number (2829820).

Almost surely, 211312143 is an apocalyptic number.

11312143 is a deficient number, since it is larger than the sum of its proper divisors (7137).

11312143 is an equidigital number, since it uses as much as digits as its factorization.

11312143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7136.

The product of its digits is 72, while the sum is 16.

The square root of 11312143 is about 3363.3529401477. The cubic root of 11312143 is about 224.4820547062.

Adding to 11312143 its reverse (34121311), we get a palindrome (45433454).

The spelling of 11312143 in words is "eleven million, three hundred twelve thousand, one hundred forty-three".

Divisors: 1 2377 4759 11312143