Base | Representation |
---|---|
bin | 10000011101011100101… |
… | …011001000101001001001 |
3 | 11000010122110221002221010 |
4 | 100131130223020221021 |
5 | 122013024042212223 |
6 | 2223345015234133 |
7 | 144502325435436 |
oct | 20353453105111 |
9 | 4003573832833 |
10 | 1131131210313 |
11 | 3a678a097085 |
12 | 163279678949 |
13 | 8288562ab90 |
14 | 3ca65c56b8d |
15 | 1e653a78393 |
hex | 1075cac8a49 |
1131131210313 has 16 divisors (see below), whose sum is σ = 1624818323520. Its totient is φ = 695810779584.
The previous prime is 1131131210303. The next prime is 1131131210347. The reversal of 1131131210313 is 3130121311311.
It is not a de Polignac number, because 1131131210313 - 218 = 1131130948169 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1131131210313.
It is not an unprimeable number, because it can be changed into a prime (1131131210303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5522406 + ... + 5723567.
It is an arithmetic number, because the mean of its divisors is an integer number (101551145220).
Almost surely, 21131131210313 is an apocalyptic number.
1131131210313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1131131210313 is a deficient number, since it is larger than the sum of its proper divisors (493687113207).
1131131210313 is a wasteful number, since it uses less digits than its factorization.
1131131210313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11248568.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 1131131210313 its reverse (3130121311311), we get a palindrome (4261252521624).
The spelling of 1131131210313 in words is "one trillion, one hundred thirty-one billion, one hundred thirty-one million, two hundred ten thousand, three hundred thirteen".
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