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1130225443213 is a prime number
BaseRepresentation
bin10000011100100110101…
…011111010000110001101
311000001022100120101001111
4100130212223322012031
5122004200203140323
62223115101412021
7144441016520146
oct20344653720615
94001270511044
101130225443213
113a6364885929
1216306626a011
138276ca95509
143c9bb838acd
151e5ee2acc0d
hex10726afa18d

1130225443213 has 2 divisors, whose sum is σ = 1130225443214. Its totient is φ = 1130225443212.

The previous prime is 1130225443211. The next prime is 1130225443231. The reversal of 1130225443213 is 3123445220311.

Together with next prime (1130225443231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 580785740649 + 549439702564 = 762093^2 + 741242^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130225443213 - 21 = 1130225443211 is a prime.

Together with 1130225443211, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130225443211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565112721606 + 565112721607.

It is an arithmetic number, because the mean of its divisors is an integer number (565112721607).

Almost surely, 21130225443213 is an apocalyptic number.

It is an amenable number.

1130225443213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130225443213 is an equidigital number, since it uses as much as digits as its factorization.

1130225443213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

The spelling of 1130225443213 in words is "one trillion, one hundred thirty billion, two hundred twenty-five million, four hundred forty-three thousand, two hundred thirteen".