1130043000109 has 2 divisors, whose sum is σ = 1130043000110. Its totient is φ = 1130043000108.

The previous prime is 1130043000083. The next prime is 1130043000131. The reversal of 1130043000109 is 9010003400311.

It is an a-pointer prime, because the next prime (1130043000131) can be obtained adding 1130043000109 to its sum of digits (22).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 928374644484 + 201668355625 = 963522^2 + 449075^2 .

It is an emirp because it is prime and its reverse (9010003400311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1130043000109 - 2⁵ = 1130043000077 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1130043000109.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130043000139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565021500054 + 565021500055.

It is an arithmetic number, because the mean of its divisors is an integer number (565021500055).

Almost surely, 2^{1130043000109} is an apocalyptic number.

It is an amenable number.

1130043000109 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130043000109 is an equidigital number, since it uses as much as digits as its factorization.

1130043000109 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 22.

It can be divided in two parts, 113004 and 3000109, that added together give a palindrome (3113113).

The spelling of 1130043000109 in words is "one trillion, one hundred thirty billion, forty-three million, one hundred nine", and thus it is an aban number.