Base | Representation |
---|---|
bin | 1010001101111001111111… |
… | …0110111000101001101111 |
3 | 1110202221222021021210112222 |
4 | 2203132133312320221233 |
5 | 2433024233442203312 |
6 | 35520501015145555 |
7 | 2236426344505322 |
oct | 243363766705157 |
9 | 43687867253488 |
10 | 11234021444207 |
11 | 364135a264751 |
12 | 131528b0752bb |
13 | 636495cc75b3 |
14 | 2aba2dbd87b9 |
15 | 147351816672 |
hex | a379fdb8a6f |
11234021444207 has 2 divisors, whose sum is σ = 11234021444208. Its totient is φ = 11234021444206.
The previous prime is 11234021444179. The next prime is 11234021444273. The reversal of 11234021444207 is 70244412043211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11234021444207 - 28 = 11234021443951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11234021440207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5617010722103 + 5617010722104.
It is an arithmetic number, because the mean of its divisors is an integer number (5617010722104).
Almost surely, 211234021444207 is an apocalyptic number.
11234021444207 is a deficient number, since it is larger than the sum of its proper divisors (1).
11234021444207 is an equidigital number, since it uses as much as digits as its factorization.
11234021444207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43008, while the sum is 35.
Adding to 11234021444207 its reverse (70244412043211), we get a palindrome (81478433487418).
The spelling of 11234021444207 in words is "eleven trillion, two hundred thirty-four billion, twenty-one million, four hundred forty-four thousand, two hundred seven".
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