Base | Representation |
---|---|
bin | 10000010101111111111… |
… | …000111101100010000011 |
3 | 10222101000000012100021102 |
4 | 100111333320331202003 |
5 | 121400133304242122 |
6 | 2215543150445015 |
7 | 144100155233312 |
oct | 20257770754203 |
9 | 3871000170242 |
10 | 1123132102787 |
11 | 3a3354879212 |
12 | 16180680376b |
13 | 81bac33b066 |
14 | 3c507742279 |
15 | 1e3366a7492 |
hex | 1057fe3d883 |
1123132102787 has 2 divisors, whose sum is σ = 1123132102788. Its totient is φ = 1123132102786.
The previous prime is 1123132102751. The next prime is 1123132102849. The reversal of 1123132102787 is 7872012313211.
It is a weak prime.
It is an emirp because it is prime and its reverse (7872012313211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1123132102787 - 236 = 1054412626051 is a prime.
It is a super-2 number, since 2×11231321027872 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1123132102787.
It is not a weakly prime, because it can be changed into another prime (1123132102087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561566051393 + 561566051394.
It is an arithmetic number, because the mean of its divisors is an integer number (561566051394).
Almost surely, 21123132102787 is an apocalyptic number.
1123132102787 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123132102787 is an equidigital number, since it uses as much as digits as its factorization.
1123132102787 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28224, while the sum is 38.
Adding to 1123132102787 its reverse (7872012313211), we get a palindrome (8995144415998).
The spelling of 1123132102787 in words is "one trillion, one hundred twenty-three billion, one hundred thirty-two million, one hundred two thousand, seven hundred eighty-seven".
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