Base | Representation |
---|---|
bin | 10000010101111111111… |
… | …000111101010110000011 |
3 | 10222101000000012022012222 |
4 | 100111333320331112003 |
5 | 121400133304231034 |
6 | 2215543150441255 |
7 | 144100155231134 |
oct | 20257770752603 |
9 | 3871000168188 |
10 | 1123132102019 |
11 | 3a3354878684 |
12 | 16180680322b |
13 | 81bac33a8c5 |
14 | 3c507741c8b |
15 | 1e3366a712e |
hex | 1057fe3d583 |
1123132102019 has 2 divisors, whose sum is σ = 1123132102020. Its totient is φ = 1123132102018.
The previous prime is 1123132102013. The next prime is 1123132102021. The reversal of 1123132102019 is 9102012313211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1123132102019 is a prime.
It is a super-2 number, since 2×11231321020192 (a number of 25 digits) contains 22 as substring.
Together with 1123132102021, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1123132102013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 561566051009 + 561566051010.
It is an arithmetic number, because the mean of its divisors is an integer number (561566051010).
Almost surely, 21123132102019 is an apocalyptic number.
1123132102019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1123132102019 is an equidigital number, since it uses as much as digits as its factorization.
1123132102019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 26.
The spelling of 1123132102019 in words is "one trillion, one hundred twenty-three billion, one hundred thirty-two million, one hundred two thousand, nineteen".
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