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112202120033 = 467240261499
BaseRepresentation
bin110100001111111000…
…1000111101101100001
3101201121120002021011022
41220133301013231201
53314242220320113
6123313412455225
711051321166323
oct1503761075541
9351546067138
10112202120033
1143648198523
12198b431a515
13a7717c1503
145605853613
152dba5d2908
hex1a1fc47b61

112202120033 has 4 divisors (see below), whose sum is σ = 112442382000. Its totient is φ = 111961858068.

The previous prime is 112202120011. The next prime is 112202120059. The reversal of 112202120033 is 330021202211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112202120033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 112202119993 and 112202120020.

It is not an unprimeable number, because it can be changed into a prime (112202129033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120130283 + ... + 120131216.

It is an arithmetic number, because the mean of its divisors is an integer number (28110595500).

Almost surely, 2112202120033 is an apocalyptic number.

It is an amenable number.

112202120033 is a deficient number, since it is larger than the sum of its proper divisors (240261967).

112202120033 is an equidigital number, since it uses as much as digits as its factorization.

112202120033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 240261966.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 112202120033 its reverse (330021202211), we get a palindrome (442223322244).

The spelling of 112202120033 in words is "one hundred twelve billion, two hundred two million, one hundred twenty thousand, thirty-three".

Divisors: 1 467 240261499 112202120033