Base | Representation |
---|---|
bin | 1010001100101100100010… |
… | …0101110111011110001111 |
3 | 1110200222022021112121211111 |
4 | 2203023020211313132033 |
5 | 2432204143340343203 |
6 | 35503141534432451 |
7 | 2235062202321634 |
oct | 243131045673617 |
9 | 43628267477744 |
10 | 11213230012303 |
11 | 3633560017180 |
12 | 1311248062727 |
13 | 634531679977 |
14 | 2aaa1a77818b |
15 | 146a3636726d |
hex | a32c897778f |
11213230012303 has 4 divisors (see below), whose sum is σ = 12232614558888. Its totient is φ = 10193845465720.
The previous prime is 11213230012279. The next prime is 11213230012319. The reversal of 11213230012303 is 30321003231211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11213230012303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11213230012343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 509692273276 + ... + 509692273297.
It is an arithmetic number, because the mean of its divisors is an integer number (3058153639722).
Almost surely, 211213230012303 is an apocalyptic number.
11213230012303 is a deficient number, since it is larger than the sum of its proper divisors (1019384546585).
11213230012303 is a wasteful number, since it uses less digits than its factorization.
11213230012303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1019384546584.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 11213230012303 its reverse (30321003231211), we get a palindrome (41534233243514).
The spelling of 11213230012303 in words is "eleven trillion, two hundred thirteen billion, two hundred thirty million, twelve thousand, three hundred three".
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