Search a number
-
+
11213213333 = 71601887619
BaseRepresentation
bin10100111000101110…
…00000111010010101
31001221110122020221112
422130113000322111
5140431040311313
65052402024405
7544605512030
oct123427007225
931843566845
1011213213333
114834626163
12220b348105
131099159c9a
14785332017
154596588a8
hex29c5c0e95

11213213333 has 4 divisors (see below), whose sum is σ = 12815100960. Its totient is φ = 9611325708.

The previous prime is 11213213321. The next prime is 11213213411. The reversal of 11213213333 is 33331231211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11213213333 - 26 = 11213213269 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11213213299 and 11213213308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11213213933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 800943803 + ... + 800943816.

It is an arithmetic number, because the mean of its divisors is an integer number (3203775240).

Almost surely, 211213213333 is an apocalyptic number.

It is an amenable number.

11213213333 is a deficient number, since it is larger than the sum of its proper divisors (1601887627).

11213213333 is an equidigital number, since it uses as much as digits as its factorization.

11213213333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1601887626.

The product of its digits is 972, while the sum is 23.

Adding to 11213213333 its reverse (33331231211), we get a palindrome (44544444544).

The spelling of 11213213333 in words is "eleven billion, two hundred thirteen million, two hundred thirteen thousand, three hundred thirty-three".

Divisors: 1 7 1601887619 11213213333