Base | Representation |
---|---|
bin | 10000010100010011011… |
… | …010010100110011001101 |
3 | 10222012022011121021010010 |
4 | 100110103122110303031 |
5 | 121332421401213201 |
6 | 2215042414303433 |
7 | 144004105602024 |
oct | 20242332246315 |
9 | 3865264537103 |
10 | 1121312132301 |
11 | 3a2600514479 |
12 | 1613991b7b79 |
13 | 8197c27814a |
14 | 3c3b3b4b8bb |
15 | 1e27ba06bd6 |
hex | 10513694ccd |
1121312132301 has 4 divisors (see below), whose sum is σ = 1495082843072. Its totient is φ = 747541421532.
The previous prime is 1121312132293. The next prime is 1121312132377. The reversal of 1121312132301 is 1032312131211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1121312132301 - 23 = 1121312132293 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1121312131301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 186885355381 + ... + 186885355386.
It is an arithmetic number, because the mean of its divisors is an integer number (373770710768).
Almost surely, 21121312132301 is an apocalyptic number.
It is an amenable number.
1121312132301 is a deficient number, since it is larger than the sum of its proper divisors (373770710771).
1121312132301 is an equidigital number, since it uses as much as digits as its factorization.
1121312132301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 373770710770.
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 1121312132301 its reverse (1032312131211), we get a palindrome (2153624263512).
The spelling of 1121312132301 in words is "one trillion, one hundred twenty-one billion, three hundred twelve million, one hundred thirty-two thousand, three hundred one".
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