Base | Representation |
---|---|
bin | 10000010100000000111… |
… | …011101011110010100001 |
3 | 10222011111120020111121212 |
4 | 100110000323223302201 |
5 | 121331303020010423 |
6 | 2214551541355505 |
7 | 143663322501164 |
oct | 20240073536241 |
9 | 3864446214555 |
10 | 1121002110113 |
11 | 3a2461515196 |
12 | 161311408b95 |
13 | 8192cc7b672 |
14 | 3c3848c9adb |
15 | 1e25e6b8578 |
hex | 10500eebca1 |
1121002110113 has 2 divisors, whose sum is σ = 1121002110114. Its totient is φ = 1121002110112.
The previous prime is 1121002110101. The next prime is 1121002110119. The reversal of 1121002110113 is 3110112001211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1005353144929 + 115648965184 = 1002673^2 + 340072^2 .
It is a cyclic number.
It is not a de Polignac number, because 1121002110113 - 216 = 1121002044577 is a prime.
It is not a weakly prime, because it can be changed into another prime (1121002110119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560501055056 + 560501055057.
It is an arithmetic number, because the mean of its divisors is an integer number (560501055057).
Almost surely, 21121002110113 is an apocalyptic number.
It is an amenable number.
1121002110113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121002110113 is an equidigital number, since it uses as much as digits as its factorization.
1121002110113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 1121002110113 its reverse (3110112001211), we get a palindrome (4231114111324).
The spelling of 1121002110113 in words is "one trillion, one hundred twenty-one billion, two million, one hundred ten thousand, one hundred thirteen".
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