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112012111027 is a prime number
BaseRepresentation
bin110100001010001110…
…0010010110010110011
3101201010022112210210201
41220110130102302303
53313400100023102
6123242504140031
711043523143235
oct1502434226263
9351108483721
10112012111027
114355aa09993
1219860767617
13a74132494b
1455c8512255
152da8a9d987
hex1a14712cb3

112012111027 has 2 divisors, whose sum is σ = 112012111028. Its totient is φ = 112012111026.

The previous prime is 112012110989. The next prime is 112012111049. The reversal of 112012111027 is 720111210211.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112012111027 is a prime.

It is a super-3 number, since 3×1120121110273 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 112012110995 and 112012111013.

It is not a weakly prime, because it can be changed into another prime (112012111067) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006055513 + 56006055514.

It is an arithmetic number, because the mean of its divisors is an integer number (56006055514).

Almost surely, 2112012111027 is an apocalyptic number.

112012111027 is a deficient number, since it is larger than the sum of its proper divisors (1).

112012111027 is an equidigital number, since it uses as much as digits as its factorization.

112012111027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 112012111027 its reverse (720111210211), we get a palindrome (832123321238).

The spelling of 112012111027 in words is "one hundred twelve billion, twelve million, one hundred eleven thousand, twenty-seven".