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111434137 is a prime number
BaseRepresentation
bin1101010010001…
…01100110011001
321202200102220021
412221011212121
5212011343022
615020230441
72522113603
oct651054631
9252612807
10111434137
11579a1131
123139b421
131a118079
1410b2a173
159bb27c7
hex6a45999

111434137 has 2 divisors, whose sum is σ = 111434138. Its totient is φ = 111434136.

The previous prime is 111434083. The next prime is 111434173. The reversal of 111434137 is 731434111.

It is a happy number.

Together with next prime (111434173) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90421081 + 21013056 = 9509^2 + 4584^2 .

It is an emirp because it is prime and its reverse (731434111) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111434137 is a prime.

It is not a weakly prime, because it can be changed into another prime (111434177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55717068 + 55717069.

It is an arithmetic number, because the mean of its divisors is an integer number (55717069).

Almost surely, 2111434137 is an apocalyptic number.

It is an amenable number.

111434137 is a deficient number, since it is larger than the sum of its proper divisors (1).

111434137 is an equidigital number, since it uses as much as digits as its factorization.

111434137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1008, while the sum is 25.

The square root of 111434137 is about 10556.2368768421. The cubic root of 111434137 is about 481.2152899686.

Adding to 111434137 its reverse (731434111), we get a palindrome (842868248).

The spelling of 111434137 in words is "one hundred eleven million, four hundred thirty-four thousand, one hundred thirty-seven".