Base | Representation |
---|---|
bin | 10000001101101101100… |
… | …011100000100000100111 |
3 | 10221112000220220001110112 |
4 | 100031231203200200213 |
5 | 121223423021220112 |
6 | 2211512225243235 |
7 | 143333525305112 |
oct | 20155543404047 |
9 | 3845026801415 |
10 | 1114234554407 |
11 | 39a5a93a3447 |
12 | 15bb42a9351b |
13 | 810c1b7c430 |
14 | 3bd01b99579 |
15 | 1deb54b6a22 |
hex | 1036d8e0827 |
1114234554407 has 4 divisors (see below), whose sum is σ = 1199944904760. Its totient is φ = 1028524204056.
The previous prime is 1114234554337. The next prime is 1114234554487. The reversal of 1114234554407 is 7044554324111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1114234554407 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1114234554487) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42855175157 + ... + 42855175182.
It is an arithmetic number, because the mean of its divisors is an integer number (299986226190).
Almost surely, 21114234554407 is an apocalyptic number.
1114234554407 is a deficient number, since it is larger than the sum of its proper divisors (85710350353).
1114234554407 is an equidigital number, since it uses as much as digits as its factorization.
1114234554407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85710350352.
The product of its (nonzero) digits is 268800, while the sum is 41.
Adding to 1114234554407 its reverse (7044554324111), we get a palindrome (8158788878518).
The spelling of 1114234554407 in words is "one trillion, one hundred fourteen billion, two hundred thirty-four million, five hundred fifty-four thousand, four hundred seven".
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