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1114234551433 is a prime number
BaseRepresentation
bin10000001101101101100…
…011011111110010001001
310221112000220212220101101
4100031231203133302021
5121223423021121213
62211512225221401
7143333525263333
oct20155543376211
93845026786341
101114234551433
1139a5a93a1193
1215bb42a91861
13810c1b7ac83
143bd01b98453
151deb54b5bdd
hex1036d8dfc89

1114234551433 has 2 divisors, whose sum is σ = 1114234551434. Its totient is φ = 1114234551432.

The previous prime is 1114234551403. The next prime is 1114234551449. The reversal of 1114234551433 is 3341554324111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 567171659664 + 547062891769 = 753108^2 + 739637^2 .

It is a cyclic number.

It is not a de Polignac number, because 1114234551433 - 29 = 1114234550921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1114234551392 and 1114234551401.

It is not a weakly prime, because it can be changed into another prime (1114234551403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557117275716 + 557117275717.

It is an arithmetic number, because the mean of its divisors is an integer number (557117275717).

Almost surely, 21114234551433 is an apocalyptic number.

It is an amenable number.

1114234551433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114234551433 is an equidigital number, since it uses as much as digits as its factorization.

1114234551433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 86400, while the sum is 37.

Adding to 1114234551433 its reverse (3341554324111), we get a palindrome (4455788875544).

The spelling of 1114234551433 in words is "one trillion, one hundred fourteen billion, two hundred thirty-four million, five hundred fifty-one thousand, four hundred thirty-three".