11142220013 has 4 divisors (see below), whose sum is σ = 11183335488. Its totient is φ = 11101104540.

The previous prime is 11142219967. The next prime is 11142220039. The reversal of 11142220013 is 31002224111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31002224111 = 7187 ⋅4313653.

It is a cyclic number.

It is not a de Polignac number, because 11142220013 - 2²² = 11138025709 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11142219973 and 11142220000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11142220613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20557331 + ... + 20557872.

It is an arithmetic number, because the mean of its divisors is an integer number (2795833872).

Almost surely, 2^11142220013 is an apocalyptic number.

It is an amenable number.

11142220013 is a deficient number, since it is larger than the sum of its proper divisors (41115475).

11142220013 is an equidigital number, since it uses as much as digits as its factorization.

11142220013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41115474.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 11142220013 its reverse (31002224111), we get a palindrome (42144444124).

The spelling of 11142220013 in words is "eleven billion, one hundred forty-two million, two hundred twenty thousand, thirteen".